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Can I remove % from a $PATH definition in zsh?

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issue: ping is not found: zsh: command not found: ping /sbin/ping -c 3 192.168.1.114 returns the expected result echo $PATH returns: /Users/user/Scripts:/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin% cat ~/.zshrc returns: export PATH=/Users/user/Scripts:$PATH% **Will removing the % in .zshrc restore /sbin to the path?** I am reluctant to simply try it out for fear of borking up a relative's computer.
Asked by gatorback (3403 rep)
Jan 24, 2024, 10:02 PM
Last activity: Jan 24, 2024, 10:24 PM