Using Postgres to return a selection based on frequency distribution

I am not even sure if this is a possibility so my apologies if I'm barking up the wrong tree; I am ignorant of Postgres's limitations as I am self-taught. This is hypothetical, but if I had a table like so: **dice_rolls** | roll_1 | roll_2 | sum | | -------- | ------- |------| | 1 | 1 | 2 | | 1 | 2 | 3 | | 1 | 3 | 4 | | 1 | 4 | 5 | | 1 | 5 | 6 | | 1 | 6 | 7 | | 2 | 1 | 3 | | 2 | 2 | 4 | | 2 | 3 | 5 | | 2 | 4 | 6 | | 2 | 5 | 7 | | 2 | 6 | 8 | | 3 | 1 | 4 | | 3 | 2 | 5 | | 3 | 3 | 6 | | 3 | 4 | 7 | | 3 | 5 | 8 | | 3 | 6 | 9 | | 4 | 1 | 5 | | 4 | 2 | 6 | | 4 | 3 | 7 | | 4 | 4 | 8 | | 4 | 5 | 9 | | 4 | 6 | 10 | | 5 | 1 | 6 | | 5 | 2 | 7 | | 5 | 3 | 8 | | 5 | 4 | 9 | | 5 | 5 | 10 | | 5 | 6 | 11 | | 6 | 1 | 7 | | 6 | 2 | 8 | | 6 | 3 | 9 | | 6 | 4 | 10 | | 6 | 5 | 11 | | 6 | 6 | 12 | we can see that the value '7' for sum appears most frequently. If we plotted the frequency distribution of the sum, it would look something like this:

x
            x  x  x
         x  x  x  x  x  
      x  x  x  x  x  x  x 
   x  x  x  x  x  x  x  x  x
x  x  x  x  x  x  x  x  x  x  x

2  3  4  5  6  7  8  9  10 11 12

Therefore, we can assume that a truly random selection of this dataset will follow this distribution pattern. What I'm interested in is psuedo-random DISTINCT selection of N rows that attempts to normalize the distribution based on the sum column. E.g.,

SELECT * FROM dice_rolls ORDER BY RANDOM() LIMIT 5;

is what I have now. This query is most likely to contain rows where the sum is 5, 6, 7, 8, 9. How would I go about using a custom ORDER BY function that would be significantly more likely (or even *strictly*) to, return rows where the sum has an even chance of being 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12?