Issues using a psql -v variable with jsonb_set

Pretty obscure situation and a couple hours of trying different things with no luck. I have a bash script which restores a production database backup locally. Part of the script runs some SQL to set things in the database. One of those items is setting the correct slack_token in a slack_details table. Here's how I run the bash script:

$ ./restore-prod-database.sh -t "xoxb-1234567-1234....."

The script has a line which triggers running a .sql file like this:

psql -h $DATABASE_HOST -d $DATABASE_NAME -a -v slack_token=$SLACK_TOKEN -f restore-populate-slack-details.sql

Finally, the SQL does something like this:

UPDATE slack_details
SET installation = jsonb_set(installation, '{bot,token}', ('"' || :slack_token ||'"')::jsonb)
WHERE id = 1;

No matter what I try, whether its concatenating the :slack_token with quotes, passing it in with quotes, using single quotes and " I get the following error: > UPDATE slack_details SET installation = jsonb_set(installation, > '{bot,token}', ('"' || :slack_token ||'"')::jsonb) WHERE id = 1; > psql:restore-populate-slack-details.sql:61: ERROR: column "xoxb" does > not exist LINE 2: ... = jsonb_set(installation, '{bot,token}', ('"' || > xoxb-12345... Quick note, installation is a jsonb column and the following code works fine, moment I use the -v variable it doesn't work:

UPDATE slack_details
SET installation = jsonb_set(installation, '{bot,token}', ('"' || '123456' ||'"')::jsonb)
WHERE id = 1; --- works fine