Possible explanation for why "SELECT" query executed from JDBC returning just the first row in the table

I installed OracleDB(XE - free version) and I tried to use it in Java. I have this code:

static final String DB_URL = "jdbc:oracle:thin:@localhost:1521/XE";
	   static final String USER = "AdministratorPDB1";
	   static final String PASS = "admin.admin";
	   static final String QUERY = "SELECT * FROM TestTable";

	   public static void main(String[] args) {

	      try(Connection conn = DriverManager.getConnection(DB_URL, USER, PASS);
	         Statement stmt = conn.createStatement();
	         ResultSet rs = stmt.executeQuery(QUERY);
	      ) {		      
	         while(rs.next()){
	            //Display values
	            System.out.print(rs.getString("fam_name"));
                System.out.print("          ");
	            System.out.print(rs.getString("giv_name"));
                System.out.print("          ");
	            System.out.print(rs.getInt("age"));
                System.out.print("          ");
	            System.out.print(rs.getString("email") + "\n");
	         }
	      } catch (SQLException e) {
	         e.printStackTrace();
	      } 
	   }

For some reason, the program seems to print just the first row from the table. I can confirm the fact that there are more entries in that table if I open Windows Command Prompt, connect using sqlplus command, and run the SELECT * FROM TestTable;, query, all three rows are printed in the command line.

I also tried to loop over the rows like this: ``` ResultSetMetaData metaData = resultSet.getMetaData(); int numCols = metaData.getColumnCount(); while (resultSet.next()) { for (int i = 1; i Now, I know I might have not given enough information for a solve, but this is all I got. This is a hard problem to debug.

OracleDB version: 21c
Java version: jdk 1.8.0