Unable to print awk'ed datum in bash script

I am dumping datum into a csv file (my_datum_file.csv). The [contents](http://www.codeshare.io/vnkkQ) are all comma seperated, and I want to find the _last_ instance of the 4th parameter (i.e. the last instance of datum regarding MX3, TMX, MSV, etc. where printed). The 5th parameter is a 'subclass' of the 4th parameter (ie TMX has 098 and 001). It is also important that the 7th parameter be "status" as opposed to "SVlts". __Q:__ I want the 10th value (which is a period of time in minutes) to convert to hours. I would like to print this value out. So from the terminal I wrote:

$ cat /home/ed/start_up_job/my_datum_file.csv | awk -F, '( $4 == "TMX" ) && ( $5 == "098" ) && ( $7 == "status" ) {print $10/60}' | tail -1`'

The end result is 1022.25 hours, which is great; I've embedded this into generic little bash script

#!/bin/bash

machine_ID="$1"
machine_number="$2"

echo "$1 $2 hours is awk -F, -v MID="$machine_id" -v MNR="$machine_number" '( $4 == MID ) && ( $5 == MNR ) && ( $7 == "status" ) {t=$10} END{print int(t/60)}' /home/ed/start_up_job/my_datum_file.csv"

so when I call my bash script from the terminal $ ./myscript.txt TMX 098 I get the following output TMX 098 hours is: 0 My expected output would be TMX 098 hours is: 1022.25 I don't know what is wrong?