Why is my program called "set" not being executed?

I've created a simple C program like so: int main(int argc, char *argv[]) { if (argc != 5) { fputs("Not enough arguments!\n", stderr); exit(EXIT_FAILURE); } And I have my PATH modified in *etc/bash.bashrc* like so: PATH=.:$PATH I've saved this program as set.c and am compiling it with gcc -o set set.c in the folder ~/Programming/so However, when I call set 2 3 nothing happens. There is no text that appears. Calling ./set 2 3 gives the expected result I've never had a problem with PATH before and which set returns ./set. So it seems the PATH is the correct one. What's is happening?