Output NamingVariable for Multiple Files in Bash Script

I have a script I've created that will pad a series of Jpgs, create a subdirectory in the working directory, move the padded Jpgs to the subdirectory, change to the subdirectory, and then use Imagemagick's convert command to overlay a single transparent .gif over the padded images. All but the last step works. If I run this script on one Jpg file it works correctly. But when I try it on multiple Jpgs it will only semi-work on one Jpg and not the others. I assume that I'm not using the correct naming variable in the last command, but I'm having no luck finding the correction. Bash script: #!/bin/bash if yad \ --image "dialog-question" \ --title "Alert" \ --button=gtk-yes:0 \ --button=gtk-no:1 \ --text "Have you resized JPGs?" then convert *.jpg "$i" -bordercolor black -border 120x0 "pad$i.jpg" mkdir -p ./padded; mv pad*.jpg $_ cd padded cp /home/mastergif/ggg.gif /home/test/padded convert ggg.gif *.jpg "$i" -background black -gravity center -compose dstover -composite $i*.jpg exec bash else exit 1 fi