How can I create an arithmetic loop in a POSIX shell script?
30
votes
3
answers
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I know how to create an arithmetic
for
loop in bash
.
How can one do an equivalent loop in a POSIX shell script?
As there are various ways of achieving the same goal, feel free to add your own answer and elaborate a little on how it works.
An example of one such bash
loop follows:
#!/bin/bash
for (( i=1; i != 10; i++ ))
do
echo "$i"
done
Asked by Vlastimil Burián
(30515 rep)
Dec 13, 2017, 01:10 PM
Last activity: Feb 7, 2022, 05:08 PM
Last activity: Feb 7, 2022, 05:08 PM