Get container directory more easily

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2 answers

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                          I have a bash script here:

    $GOPATH/
         src/
         build.sh

and in build.sh I have:

    export GOPATH="$(cd $(dirname "$BASH_SOURCE") && pwd)"

is there a shorter way to get the containing dir of build.sh?

Asked by Alexander Mills (10744 rep)

Oct 19, 2018, 06:52 AM
Last activity: Oct 23, 2018, 01:14 AM

Get container directory more easily

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