How can I run the sudo command in Python code under CentOS in Docker

I am trying to access the docker image labels from Python as follows hostname = socket.gethostname() cmd = "sudo curl --unix-socket /var/run/docker.sock http:/containers/" + hostname + "/json" output = os.popen(cmd).read() But, the thing is I am getting the following error: We trust you have received the usual lecture from the local System Administrator. It usually boils down to these three things: #1) Respect the privacy of others. #2) Think before you type. #3) With great power comes great responsibility. sudo: no tty present and no askpass program specified It's one of the fancy messages by Unix from some other posts I read from StackOverflow. I am following the below link https://stackoverflow.com/questions/37439887/how-to-access-the-metadata-of-a-docker-container-from-a-script-running-inside-th Only thing is I want to run these things from Python not from the Terminal. Also, FYI, I get the response when I run the same command from the terminal. I tried appending the following piece in Dockerfile RUN echo "root ALL=(ALL) NOPASSWD:ALL" >> /etc/sudoers Thanks