Use a shell variable in awk

Here is my script (to find the files that contain a specified pattern): find . -type f \ -exec awk -v vawk="$1" '/'"$vawk"'/ {c++} c>0 { print ARGV; exit 0 } END { if (! c) {exit 1}}' \{\} \; I would like to use my script with an argument §: MyScript.sh pattern My problem is that I don't manage to put the $1 variable in awk. When I try to debug my script bash -x MyScript.sh pattern Here is the output : + find . -type f -exec awk -v vawk=pattern '// {c++} c>0 {print ARGV ; exit 0 } END { if (! c) {exit 1}}' '{}' ';' The $vawk variable seems to be empty. Any idea?