$@ in alias inside script: is there a "local" $@?

I have aliased pushd in my bash shell as follows so that it suppresses output: alias pushd='pushd "$@" > /dev/null' This works fine most of the time, but I'm running into trouble now using it inside functions that take arguments. For example, test() { pushd . ... } Running test without arguments is fine. But with arguments: > test x y z bash: pushd: too many arguments I take it that pushd is trying to take . x y z as arguments instead of just .. How can I prevent this? Is there a "local" equivalent of $@ that would only see . and not x y z?