Read file line by line with awk to replace characters in certain line numbers

I have got this script here. It is supposed to run the loop by reading the file LineNumbers.file line by line (each contains a line number) and then accordingly replacing 0/0 with ./. in the BEFORE_File.txt. It works, but it takes only the very last line of the file LineNumbers.file, instead of the >100 entries. I am not sure what I am doing wrong here. Can you please help me to get awk to read the LineNumbers.file line by line? I have got it to work with sed -i "${line}s/0\/0/\.\/\./" "${myFileTmp}", but it was really slow on the >3GB large files that I have got. So I thought that awk would be a faster option. Many thanks!

cat ./LineNumbers_TEMP/LineNumbers.file | while read line
do
myFileTmp=BEFORE_File.txt
awk -v var=${line} 'FNR==var { sub(/0\/0/, "\.\/\."); print }' "${myFileTmp}" > AFTER_File.txt
done

For example this is how the files look like:

cat ./LineNumbers_TEMP/LineNumbers.file
1
2
5

File.txt before script:

cat BEFORE_File.txt
0/0
0/0
0/1
0/1
0/0
0/0
0/0

This is how the file should look after running the script:

cat AFTER_File.txt
./.
./.
0/1
0/1
./.
0/0
0/0

At the moment I get only this:

./.