Get the size of a S3 Bucket's sub-folder through bash script

I am trying to write a bash script to get the total size of sub folders in a S3 bucket. My bucketpath **s3://path1/path2/subfolders** Inside the path2 folder i have many sub-folder like 2019_06 2019_07 2019_08 2019_09 2019_10 2019_11 2019_12 I need to get the size of each subfolder in a bash script. I wrote a script like ** #!/bin/bash FILES=$(mktemp) aws s3 ls "s3://path1/path2/" >> "$FILES" cat $FILES echo for file in $FILES do if [ ! -e "$file" ] then s3cmd du -r s3://path1/path2/$file echo "$file"; echo continue fi echo done ** The output of cat $tmpfile is as below 2019_06 2019_07 2019_08 2019_09 2019_10 2019_11 2019_12 But am getting error. While passing the variable into the for loop. Ideally my aim is like for each iteration when for loop runs inside do .....The command should be like **s3cmd du -r s3://path1/path2/2019_06** **s3cmd du -r s3://path1/path2/2019_07** **s3cmd du -r s3://path1/path2/2019_08** etc... So that i can get the total size of the folder Kindly help!