`set -x` debugging my `.zshrc`

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3 answers

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shell-script command-line zsh debugging set

                          When I use set -x to debug a command it output some extra lines.

    % set -x
    +precmd_update_git_vars:1> [ -n '' ']'
    +precmd_update_git_vars:1> [ '!' -n '' ']'
    +precmd_update_git_vars:2> update_current_git_vars
    +update_current_git_vars:1> unset __CURRENT_GIT_STATUS
    +update_current_git_vars:3> [[ python == python ]]
    +update_current_git_vars:4> _GIT_STATUS=+update_current_git_vars:4> python /home/ismail/zshfiles/gitstatus.py
    +update_current_git_vars:4> _GIT_STATUS='' 
    +update_current_git_vars:6> __CURRENT_GIT_STATUS=( '' ) 
    +update_current_git_vars:7> GIT_BRANCH='' 
    +update_current_git_vars:8> GIT_AHEAD='' 
    +update_current_git_vars:9> GIT_BEHIND='' 
    +update_current_git_vars:10> GIT_STAGED='' 
    +update_current_git_vars:11> GIT_CONFLICTS='' 
    +update_current_git_vars:12> GIT_CHANGED='' 
    +update_current_git_vars:13> GIT_UNTRACKED='' 
    +precmd_update_git_vars:3> unset __EXECUTED_GIT_COMMAND

I can't debug my commands because of these outputs.

Why is set -x debugging my .zshrc? I want set -x to debug only the lines followed by set -x.
                        

Asked by Ahmad Ismail (2998 rep)

Jul 4, 2020, 04:29 PM
Last activity: Feb 1, 2023, 01:54 AM

`set -x` debugging my `.zshrc`

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