[ moving the question from StackOverflow where it seems less appropriate ]
The kernel boots with
default_hugepagesz=1G
option, which defines size of the default page size. So when an application want large memory, the kernel will allocate it with 1G pages.
If the kernel boots with hugepages=N
, i.e. allocate N huge pages at boot. So in this case, the kernel will automatically take a page from this pool, thus saving time on allocating memory?
When this pool runs out of available pages, how will the kernel allocate huge memory?
Asked by Mark
(1943 rep)
Dec 30, 2020, 05:11 PM
Last activity: Dec 30, 2020, 07:19 PM
Last activity: Dec 30, 2020, 07:19 PM