List only files and not directories in archive

I have a zip achieve like below $ unzip -l 5124.zip Archive: 5124.zip Length Date Time Name --------- ---------- ----- ---- 0 01-13-2021 09:22 u/ 0 01-13-2021 09:22 u/MyCom/ 0 01-13-2021 09:22 u/MyCom/UNX/ 0 01-13-2021 09:22 u/MyCom/UNX/scripts/ 0 01-13-2021 09:22 u/MyCom/UNX/scripts/SYNC/ 0 01-13-2021 09:22 u/MyCom/UNX/scripts/SYNC/sql/ 48704 01-13-2021 01:50 u/MyCom/UNX/scripts/SYNC/sql/Load.sql 41872 01-13-2021 01:00 u/MyCom/UNX/scripts/SYNC/sql/Update1.sql --------- ------- 90576 8 files I want to just get the filenames in the archive while ignoring the rest which in the above case is /u/MyCom/UNX/scripts/SYNC/sql/Load.sql /u/MyCom/UNX/scripts/SYNC/sql/Update1.sql Note: The preceding / is missing from the output of unzip this I need /u/MyCom/UNX/scripts/SYNC/sql/Load.sql /u/MyCom/UNX/scripts/SYNC/sql/Update1.sql and not u/MyCom/UNX/scripts/SYNC/sql/Load.sql u/MyCom/UNX/scripts/SYNC/sql/Update1.sql Any good way to get this info from any given zip ?