Capturing comment character from matching pattern

I would like to pick out lines from a file matching # Mode: org # can be any comment character for the programming language of the file. Rather than #, in could also be any of ; or !, with any preceeding number of spaces using a bash script. Examples # Mode: org ;; Mode: org !! Mode: org One could figure out the language from the file extention .el emacs .c c .cc c++ .sh bash .rc bash .f fortran .F fortran .f90 fortran .texi texinfo .tex tex This is the current bash function I am using capture () { local efile="$1" local begorg endorg charcl impl="1" if [ "$impl" = "1" ]; then charcl='^[[:space:]]*(#|;|!)+[[:space:]]*' elif [ "$impl" = "2" ]; then charcl='^[[:space:]]*(//|@c)[[:space:]]*' fi begorg="${charcl}"'Mode: org$' endorg="${charcl}"'# End of org$' awk -v ccls="$charcl" -v bego="$begorg" -v endo="$endorg" \ '$0 ~ bego { found=1; next } $0 ~ endo { found=0; } found { sub(/ccls/,""); print }' "$efile" } Would be better to this in awk, but I struggle on how to include the pattern. // { set variable to A } /other pattern/ { set variable to B } ... use variable in sub