Bash: converting a string with both spaces and quotes to an array

I have a function (not created by me) that outputs a series of strings inside of quotes: command “Foo” “FooBar” “Foo Bar” “FooBar/Foo Bar” When I try to assign it to an array (Bash; BSD/Mac), instead of 4 elements, I get 7. For example, for ${array} I *should* get “Foo Bar”, but instead, I get ”Foo with the next element being Bar”. Any element *without* the space works correctly (i.e. ${array} = “Foo”) **How can assign each of these elements between the quote including the space to an array that the elements are separated by spaces(?) themselves?** Right now, I am thinking of using sed/awk to “strip” out the quotes, but I think there should be a better and more efficient way. Currently, I am assigning the output of the command (looks exactly like the output above including the quotes) to a temporary variable then assigning it to an array. _tempvar=“$(command )” declare -a _array=(${_tempvar})