tying together the 'xxd' command with output

I have the following hex dump: 00000000: 2345 5854 5241 530a 0a31 2e20 746f 2061 #EXTRAS..1. to a 00000010: 6464 2075 7365 723a 2060 7375 646f 2075 dd user: `sudo u 00000020: 7365 7261 6464 205b 7573 6572 6e61 6d65 seradd [username 00000030: 5d60 2061 6e64 2074 6865 6e20 6073 7564 ] and then sud 00000040: 6f20 7061 7373 7764 205b 7573 6572 6e61 o passwd [userna 00000050: 6d65 5d60 2074 6f20 6164 6420 7061 7373 me]` to add pass 00000060: 776f 7264 0a0a 312e 2074 6865 2063 6f6d word..1. the com 00000070: 6d61 6e64 2061 626f 7665 2077 696c 6c20 mand above will 00000080: 6e6f 7420 6164 6420 6120 686f 6d65 2064 not add a home d 00000090: 6972 6563 746f 7279 2066 6f72 2074 6865 irectory for the 000000a0: 2061 6464 6564 2075 7365 720a 0a31 2e20 added user..1. 000000b0: 746f 2067 6976 6520 7468 6520 7573 6572 to give the user 000000c0: 2061 2068 6f6d 6520 6469 7265 6374 6f72 a home director 000000d0: 792c 2069 6e63 6c75 6465 2074 6865 2060 y, include the ` 000000e0: 2d6d 6020 666c 6167 0a0a 0a -m` flag... vim is telling me its 235b and simple command I wrote to count all characters is telling me there are 243 characters: xxd -ps extras.md | sed 's/\(..\)/\1\n/g' | wc -l in addition, the left memory column is telling its taking up: 'd0 + 11 bytes so 219 bytes'? If I'm understanding that right. can someone tie 219, 235 and 243 together for me? or tell me i did everything wrong that works too but let me know how to fix please