Zsh Expanding Variables into Arrays or Lists

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zsh variable array variable-substitution

                          I looked through some of the posted threads and none of them cover my query.

I have a simple line of code below which prints all the ASCII characters:

    echo {' '..'~'}
I want to be able to use a variable to substitute this array like below

    list="{' '..'~'}"

and then do the following

    echo $(print ${list})

To clarify what I am trying to do:

    passwordLength="2"

    for (( i = 0; i < $passwordLength; i++ ))
    do
    	# concatenate random characters
    	samplePasswordRegex="$samplePasswordRegex{' '..'~'}"
    done
    
    echo $^samplePasswordRegex
                        

Asked by James Bond (29 rep)

Oct 18, 2024, 07:28 PM
Last activity: Oct 24, 2024, 09:24 PM

Zsh Expanding Variables into Arrays or Lists

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