bash - slice quoted substrings delimited by spaces into array

following example:

string=" 'f o o' 'f oo' 'fo o' "
array=($string)
echo "${array}"

outputs:

'f

while the expected output is:

'f o o'

The only solution I came with is by changing the delimiter to newline (rather than space):

IFS=$'\n'
string="'f o o' # 'f oo' # 'fo o' #"
array=($(echo "$string" | tr '#' '\n'))
echo "${array}"

outputs:

'f o o'

which outputs the expected result, however this requires to set a custom delimiter in string and it's will invoke a new subprocess on each call. I would like to see a better solution than this, thanks you! **Edit:** The above example string should be enough, but since some has asked what the file contents looks like, it's something similar to this:

'magic1' 'some text' 'another simple text' 'some t£xt'
'magic2' 'another line with simple text' 'foo bar' 'yeah another substring'
'magic3' 'so@m{e$%& te+=*&' 'another substring' 'here is the substring'
'magic4' 'why not another line !' 'yeah I like that' 'the substring yeah !!!'

Even more details (as some users requested): there is a custom function which uses grep to return the line from the above file by using a magic substring. for example my find function similar to this:

_find()
{
   string="$(grep "$1" "$file")"
}

then I call it like this:

_find "magic2"
echo "$string"

which outputs:

'magic2' 'another line with simple text' 'foo bar' 'yeah another substring'

P/S: each substring is delimited by space, and each substring are quoted with single quotes. editing the _find is not possible since it's used by other functions. please see the comments for more.