Run in background avoiding any job control message from the shell

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                          Lets define a shell function (here the shell is Bash) and test it

    $ s () { xterm -e sleep 5 & }
    $ s
     307926
    $ 
    +  Done                    xterm -e sleep 5
    $ 

With my specific meaning of *better*, I can redefine s like this

    $ s () { xterm -e sleep 5 & disown ; }
    $ s
     307932
    $ 
    $ 

(no message from the shell when the job is finished).

Here I have to ask, is it possible to define s so that I have

    $ s () { pre_magic xterm -e sleep 5 post_magic ; }
    $ s
    $ 
    $ 

i.e., suppress the job info printed on terminal by the shell?


                        

Asked by gboffi (1376 rep)

Apr 17, 2025, 01:52 PM
Last activity: Apr 17, 2025, 02:21 PM

Run in background avoiding any job control message from the shell

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