How to trim directory from which output without basename?
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answer
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For a shell script I need to call an executable by name, regardless of the path leading there; thus far I know this code reports the right name:
tmpprog=which program
prog=${tmpprog%%*/}
if $prog=""
then
echo >&2 "Main Program not found"
else
echo >&2 "$prog"
fi
How can I cut the code so that I may trim the path to keep the executable name and remove the path in a one liner?
Beware: basename
won't do it, since I may be working on a hybrid environment (cygwin/busybox on windoze), and sometimes the paths have spaces.
Asked by jarnowy
(200 rep)
Jan 16, 2024, 02:14 AM
Last activity: Apr 5, 2024, 08:31 AM
Last activity: Apr 5, 2024, 08:31 AM