I've been thinking about discontinuing the use of GNU Coreutils on my Linux systems, but to be honest, unlike many other GNU components, I can't think of any alternatives *(on Linux)*. What alternatives are there to GNU coreutils? will I need more than one package? Links to the project are a must, bonus points for naming distro packages. Also please don't suggest things unless you *know* they work on Linux, and can reference instructions. I doubt I'll be switching kernels soon, and I'm much too lazy for anything much beyond a straightforward ./configure; make; make install. I'm certainly not going to hack C for it. ***warning:** if your distro uses coreutils removing them could break the way your distro functions. However not having them be first in your $PATH shouldn't break things, as most scripts should use absolute paths.*

I want to **find** some files, in a non GNU environment - in the current directory only - with extension **\*.ext1** and **\*.ext2**, - but not **name1.\*** or **name2.\*** The following command works, but may be not efficient, because the shell expands ./* and **find** can get a huge list of files and directories. find ./* -prune \( -name '*ext1' -o -name '*ext2' \) -a ! \( -name 'name1*' -o -name 'name2*' \) **Update:** I'm working on AIX, there is no **-maxdepth** option.

[edit: clarified that I need an *in awk* solution, and corrected that I need to sort 'indexes' (or rather, output them in a sorted way) instead of the ambiguous 'values')] In awk, I often count things, or store a set of values, inside an array, using the values as indices (taking advantage of awk's indexes_are_hashes mechanism) For example: if I want to know how many different values of $2 I encountered, and how often each values were seen: awk ' ... several different treatments ... { count[$2]++ } ... other treatments ... END { for(str in count) { print "counted: " str " : " count[str] " times." ... and other lines underneath, with additional infos ... } } ' The problem is that (non GNU, or other nicer versions) regular awk (and regular nawk) : - [A] doesn't output the different values in the order it has 'encountered' them, - [B] nor provide an easy way to go through the indexes either in numerical or alphabetical order for [A]: not too difficult to do .. just have another array to index the "newly seen" entries. the QUESTION is for [B]: **How can I do a simple call to sort to reorder the display of the different indexes?** (note : I am aware that gnu awk has an "easy" way for [B]: https://www.gnu.org/software/gawk/manual/html_node/Controlling-Array-Traversal.html ... But I want the way to do something similar in regular awk/nawk !) (ie: I need to do a loop to output the different indexes seen, sort them, re-read them [in an old awk...] into "something" ( ex: another array ordered_seen ?) and use that something to display the seen[s] in the chosen order. And this needs to be *inside awk* as under each indexes I often need to output a paragraph of additional infos. A "sort" outside of awk would reorder everything) So far: I find no "axiomatic" one-liner (or n-liner?) way to do that. I end up with a kludge that takes several lines, outputs each values to a file through sort, and then re-reads that sorted file and insert each line in order into a sorted_countindexes[n++], and then for(i=0;ifileA printf 's f g r e d f g e z s d v f e z a d d g r f e a\ns d f e r\n'>fileB # and the awk loop: It outputs in 'whatever order', I want in 'alphabetical order' for f in file? ; do printf 'for file: %s: ' "$f" tr ' ' '\n' < "$f" | awk ' { count[$0]++ } END { for(str in count){ printf("%s:%d ",str,count[str]) }; print "" } ' done #this outputs: for file: fileA: d:3 e:5 f:3 g:1 r:4 s:6 z:2 a:5 b:1 c:3 for file: fileB: d:5 e:5 f:5 g:3 r:3 s:3 v:1 z:2 a:2 # I'd like to have the letters outputted in alphabetical order instead!

On the Unix Bash commandline, I want to calculate the date from 1125 days ago using the base operating system (e.g. No Perl or Python). On systems running GNU Date , I can do something like this: ubuntu $ date --date="1125 days ago" Wed Nov 7 15:12:33 PST 2007 FreeBSD or MacOSX systems don't ship with GNU Date, and don't support values like "X days ago". freebsd81 $ date --date="+1125 days ago" date: illegal option -- - I *can* calculate a date from a few days ago on a Mac or FreeBSD system, but this is limited to a few days: # Today is really Dec 6, 2010. 4 days ago it was: macosx $ TZ=GMT+96 date +%Y%m%d 20101202 # But that doesn't work if I want to see the date 8 days ago: macosx $ TZ=GMT+192 date +%Y%m%d 20101206 Can I calculate old dates on non-GNU systems without delving into tools like Perl or Python? Or must I use a more powerful scripting language?

The LSB is a specification, and as such, should be provider neutral. But it contains many “hard‑coded” reference to GNU at many places. Ex. the ELF Linux's specific entries PT_GNU_STACK, PT_GNU_RELRO and al., or with some libraries like libgcc_s. How these explicit references to GNU in the LSB should be interpreted? * Is it there for historical reasons (like the MZ magic in one of the Windows executable formats)? * Is it there to designate GNU as a unique provider for some parts of conforming systems? * Is it there as an acknowledgement of some role played (currently or in the paste) without any particular mandate? I would not have asked this questions, if the references did not appeared in a standard specification, I mean, the questions should be understood in this particular context.