What characters match the following regex :

^[a-zA-Z]$

Specifically, should characters with accents (eg. á, è, ò) match this regex? Or just 26 lower and upper case alphabets? I have tried to [check this](https://regex101.com/r/KN4fgg/1) in an online regex, and accented characters did not match. When I tried it out with grep on my Linux (Ubuntu) machine it **did match** the accented characters. While rg(ripgrep) **did not match** it. I can match accented characters with rg using [A-zÀ-ÿ] But is there a way to exclude accented characters from matching in grep? PS: [This](https://unix.stackexchange.com/questions/505477/grep-to-find-a-word-matching-a-specific-pattern-and-ignore-accents) question talks about how accented chars can be included, not excluded.

Suppose I have a script containing something like VAR=${VAR1%.*} I'm looking for a command along the lines of rg "${.*%" to find it, but I can't get anywhere near. all of these fail rg "\$\{.\*%" rg \$\{.\*% rg "\$\{.*%" rg \$\{.*%

I'm on Linux Ubuntu 18.04 and 20.04. Ripgrep (rg) can output a list of paths to files containing matches like this:

# search only .txt files
rg 'my pattern to match' -g '*.txt' -l
# long form
rg 'my pattern to match' --glob '*.txt' --files-with-matches

Output will be: > path/to/file1.txt > path/to/file2.txt > path/to/file3.txt etc. I'd like to then run another command on each path, such as tree $(dirname $PATH), to get a list of all files in the directory containing the matching file. How can I do that? I feel like xargs might be part of the answer maybe? But piping to xargs like this as a start seems to only handle the last-printed file:

rg 'my pattern to match' -g '*.txt' -l | xargs -0 -I {} dirname {}

Note: if you can demo with grep too that might be useful too for those without ripgrep, albeit ripgrep is super easy to install . ## References: 1. https://unix.stackexchange.com/questions/453183/ripgrep-print-only-filenames-matching-pattern/453188#453188

I just want to share this, and hoping will get more similar tool. I got a directory of text files.. i need to search for the files with 2 (partial) words in it.. the keywords are in random order, but on a same line. So far, i can use this: $ rg -i '\w*keyword1\w*.*\w*keyword2\w*|\w*keyword2\w*.*\w*keyword1\w*' --glob '*.txt' --line-number -l /path/to/search $ rg -g '*.txt' -l -i 'keyword1.*keyword2|keyword2.*keyword1' /path/to/search Both of these can do the same job. Anybody have other that can do the same job ? Pls do share. I found myself need this quite often to locate the proper file.. However i don't know how to search file that filename is 2 keywords that are not in order. How about searching for filename with 2 keyword that is not in order ? Example: weirdfilename_key1Nkey3Nkey2etc.txt search among huge database for file with which name only remember consist of "key2" and "key3" in it, but not sure the order..

I have a command like rga --files-with-matches --count-matches --sort path -i -e "use cases?" -e "user stor(y|ies)" -e "Technical debt" -e "Code Quality" -e "software development" -e "Agile Manifesto" The output is like a1.pdf:18 a2.pdf:10 a3.pdf:14 .... Here, :NUM is number of matches. I want all files who have more than 10 matches (without the colon and number, so that I can pipe the output to another command). Like: a1.pdf a3.pdf .... I tried .. | cut -d':' -f2 but it only give the number. .. | cut -d':' -f1 only gives the file name. What might be the solution here?

I have a file that contains the some python code. There is a line that contains the following(including the quotes) 'hello "value"' I want to search 'hello "value" in the file. Notice the unclosed quote. I'm using ripgrep with the folowing command: rg -F 'hello "value" The above command is not working for the input 'hello "value" in bash/ zsh. All i want is the literal match. I have used the flag F but because of unclosed quotes in the input string it is not working at all. I also tried enclosing the input inside single/ double quotes as so: rg -F "'hello "value"" or rg -F ''hello "value"' The above is not working as well. I thought the F flag would tell ripgrep to consider the input literally as it is? How do I fix this?

I'd like to search all git tracked files that 1. has an .hs file extension and 2. contain the word import in any lines. I've tried to use git ls-files -z | xargs -0 rg -g '*.hs' "import" however unfortunately if you pass an explicit list of files to rg it seems to ignore the -g glob flag. I could potentially use grep to use some regex lookbehind to extract files with a specific file extension, or potentially filter the output from git ls-files -z (ensuring we keep the null separated filenames aspect, both approaches seem a bit clunky though... If anyone has any ideas.

Probably a rooky question, but I have seen that the "rankmirrors" command can use the **stdin** input. But when I run the following command (which retrieve all URL in use in the "mirrorslist" file to the "rankmirrors"), I get an error:

Bash
$ rg -e "^Server" /etc/pacman.d/mirrorlist | rg -oe "https.*"  | rankmirrors -t
Must specify URL, mirrorfile, or stdin.

There is another way to use the previous command **stdout** as current **stdin** of the command ?

How can I can I find files that contain a specific pattern **on a specific line number** ? Let's assume I have a directory with a bunch of text files containing 3 lines, such as:

Title A
Category X
Description Y

How can I grep / filter every files that have Category X on line 2? How can I find files that have Title A as line 1? I looked at the grep man page, ripgrep and alternative but not sure you can limit the search of a pattern to specific line numbers.

How to use ripgrep to find adjacent duplicated words. for example one hello hello world How to locate hello hello by using ripgrep? Solved ---- rg '(hello)[[:blank:]]+\1' --pcre2 <<<'one hello hello world'

Using [ripgrep (rg)](https://github.com/BurntSushi/ripgrep) , can I print only the filenames which match a given pattern? There are two separate things I'm trying to do: 1. Match the pattern to the pathname itself (like ag -g pattern) 1. Match the pattern to the contents of the file and print only the filename I can't work out how to do either one.

I'm new to z shell and ohmyz.sh. I have the following in my zshrc to integrate fzf with rg. This is exactly how it appears in the fzf readme:

FZF_BASE=/usr/local/bin
DISABLE_FZF_AUTO_COMPLETION="true"
DISABLE_FZF_KEY_BINDINGS="true"
INITIAL_QUERY=""
RG_PREFIX="rg --column --line-number --no-heading --color=always --smart-case "
FZF_DEFAULT_COMMAND="$RG_PREFIX '$INITIAL_QUERY'" \
  fzf --bind "change:reload:$RG_PREFIX {q} || true" \
      --ansi --disabled --query "$INITIAL_QUERY" \
      --height=50% --layout=reverse

It kind of works but I'm seeing some weird and broken behavior: 1. The weird behavior is that when I reload zshell, fzf fires up immediately without me hitting a key or typing in the command. It works perfectly, otherwise, though. 2. The broken behavior is that when I manually type in fzf, the search is initiated but FZF_DEFAULT_COMMAND is set to what the plugin uses. I tried fixing this behavior by slapping export in front of FZF_DEFAULT_COMMAND but then when I reload zsh, I get an error: /Users/me/.zshrc:export:313: not valid in this context: --bind Next I turned the ohmyzsh plugin off and modified my code to this:

FZF_DEFAULT_COMMAND="$RG_PREFIX '$INITIAL_QUERY'" \
  fzf --bind "change:reload:$RG_PREFIX {q} || true" \
      --ansi --disabled --query "$INITIAL_QUERY" \
      --height=50% --layout=reverse
export FZF_DEFAULT_COMMAND

This kind of works, but again, it fires up fzf as soon as I load zsh. And the formatting of the search is mangled and ugly with ansi characters.

I'd like ripgrep to search paths with the specified pattern. For e.g.

rg PATTERN --path REGEX

where PATTERN is the pattern to grep and REGEX is the path matching pattern. I have scattered through the documentation and I am unsure if this functionality is baked in.

Suppose an input.txt file that contains several strings as the following ones: [[foo>a|a]] [[foo>b|b]] [[foo>c|c]] that I'd like to replace by: :foo:a :foo:b :foo:c I guess I could manage to achieve this result with sed or rg (I never used awk). But this file also contains other strings as the following ones: [[foo>a|d]] [[foo>b|e]] [[foo>c|f]] that I'd like to replace by: :foo:d :foo:e :foo:f All my attempts failed because I don't see how to handle two different patterns at once. Do you know some ways to achieve the latter result (and, BTW, the former)?