I have 25GB text file that needs a string replaced on only a few lines. I can use sed successfully but it takes a really long time to run. sed -i 's|old text|new text|g' gigantic_file.sql Is there a quicker way to do this?

Another user helped me earlier to fix something I'm doing with awk, where I search for a string at any point in all files and replace two numbers in the same line when I find it. awk -i inplace '/^gene_height/{ $3=sprintf("%.0f",(169+rand()*51));$5=sprintf("%.0f",(169+rand()*51)) }1' * This worked in the test files that I made (much fewer tags to read), but then in the actual files I'm trying to change for a Crusader Kings mod it's getting blocked because each line in the config file starts with a space then two tabs. I tried removing the "^" before gene_height and that kind of works, but it removes the space and two tabs from the file which might mess up the format and break the mod. Does anyone know how I can get the above script to read files that start with a space, two tabs, THEN the string "gene_height", and keep the space and two tabs when doing the replacement?

I have a CSV with unix line endings, but some of the string values have windows line endings in them: date,notes\n 2014-01-01,"Blah Blah Blah"\n 2014-01-02,"Two things:\r\n - first thing\r\n - second thing\n 2014-01-03,"Foo"\n Note that \n and \r just show where the non-printable characters are in the file, it's not how it would look if you opened it in a text editor. **I want to remove instances of \r\n, but keep the actual line endings, where it's just \n.** The output should look like: date,notes\n 2014-01-01,"Blah Blah Blah"\n 2014-01-02,"Two things: - first thing - second thing\n 2014-01-03,"Foo"\n I need something like tr -d '\r\n' file.csv but where it deletes the string \r\n, rather than either \r or \n. If I try to process it with sed it's treated like so when processing line-by-line, so it doesn't really work: date,notes 2014-01-01,"Blah Blah Blah" 2014-01-02,"Two things:\r - first thing\r - second thing 2014-01-03,"Foo"

A typical latex problem: \SomeStyle{\otherstyle{this is the \textit{nested part} some more text...}} Now I want to remove all \SomeStyle{...} but not the content. Content contains nested braces. The line above should become: \otherstyle{this is the \textit{nested part} some more text...} Questions: 1. Does any latex editor offer a way to do it? 2. What editor/script does it? 3. How to do it with sed? [🤓] My solution is a bash script using sed. 1. prepare text: mark replace string with ascii bell, add newline after each brace 2. loop: find { -> add X to hold space, find } -> remove X from hold space, hold space empty -> remove closing } 3. restore newlines and ascii bell to previous The script works but fails with: \badstyle{w}\badstyle{o}\badstyle{r}\badstyle{d} Iit will become: wo}rd} the branching to :f seems not to work. F=$(sed 's|\\|\\\\|g;s|{|\\{|g' <<< "$1" ) # mark all removestrings with ascii bell and newline # add newline after each { and } SEDpre=' s|'"$F"'|\a%\n|g s|\{|\{\n|g s|\}|\}\n|g ' SEDpost=' :a;N;$!ba; s|\a%\n||g s|\{\n|\{|g s|\}\n|\}|g ' # count the brackets SED=' /\a%/{ :a n :f /\{/{x;s|$|X|;x;ba} /\}/{x; s|X||; /^$/{x;bb} x ba } } b :b /\}/{ s|\}||; N; s|\n||; /\a%/bf } ' sed -r -E "$SEDpre" "$2" | sed -rE "$SED" | sed -rE "$SEDpost"

How do I replace current word under cursor in Emacs? I know that I can use query-replace or replace-string but every time I do so I have to type entire string to be replaced, this is just annoying. Vi has equivalent command cword and I can use a shortcut to pull the word under cursor for replacement: nmap z :%s#\=expand("")\># Anybody know how to do it with Emacs?

I want to use sed to search for line breaks that are not preceded by }. The regex for identifying theses cases is: [^}]$ . What I want to say: If the line ended without } then remove the new line. Any line should end with } before the newline. How to put that in sed to remove them? **EDIT:** Example: {'Date': 'Fri, 19 Apr 2019 07:23:14 GMT', 'Server': 'Apache', 'Vary': 'Qualys-Scan', 'Strict-Transport-Security': 'max-age=31536000;includeSubDomains;preload', 'Set-Cookie': 'ASP.NET_SessionId=ivoa5bhet0s2ygkylmimvkie; path=/; secure; HttpOnly;SameSite=strict, SC_ANALYTICS_GLOBAL_COOKIE=12f133ea; expires=Thu, 19-Apr-2029 07:23:14 GMT; path=/; secure; HttpOnly;SameSite=strict, SC_ANALYTICS_SESSION_COOKIE=336B5|1|ivoa5; path=/; secure; HttpOnly;SameSite=strict, incap_ses_885_270026=cDp/VlO1AHgshF9F6SZID==; path=/; Domain=.zurich.co.uk, ___utmvm=dlNaoEsuXSO; path=/; Max-Age=900, ___utmvay=nWJx01KvGT; path=/; Max-Age=900, ___utm=JZy XEtOwalQ: PtR; path=/; Max-Age=900', 'X-Content-Type-Options': 'nosniff', 'X-XSS-Protection': '1; mode=block', 'Cache-Control': 'private', 'Content-Type': 'text/html; charset=utf-8', 'Keep-Alive': 'timeout=5, max=10', 'Connection': 'Keep-Alive', 'X-Iinfo': '8-3925806-3807 NNNN CT(73 151 0) RT(155583 5) q(0 0 3 0) r(6 6) U5', 'X-CDN': 'Incapsula', 'Content-Encoding': 'gzip', 'Transfer-Encoding': 'chunked'} When I applied your script, it combined the lines. However, the new line starts with tab. How to also remove the spaces if the newline starts with spaces?

I'm using awk '{ gsub(/BAR|WIBBLE/, "FOO"); print }' to replace text in data like: SOMETHING [BAR, WIBBLE] SOMETHING [BAR] This gives the desired result of: SOMETHING [FOO, FOO] SOMETHING [FOO] But now I've had to update the text that requires replacing to be something like: awk '{ gsub(/BAR|WIBBLE|ME/, "FOO"); print }' Which turns text like: SOMETHING [ME, WIBBLE] into: SOFOOTHING [FOO, FOO] How can I limit my replacement to just the text between the brackets (i.e. leave the SOMETHING alone)? **EDIT** I also need robustness across whatever text SOMETHING might be (e.g. SHE GAVE ME THAT shouldn't have ME replaced).

I'd like to know if there is a way that I could cat file like php.ini and remove all lines starting with ; For example, if the file contained this: ; - Show all errors, except for notices ; ;error_reporting = E_ALL & ~E_NOTICE ; ; - Show only errors ; ;error_reporting = E_COMPILE_ERROR|E_ERROR|E_CORE_ERROR ; ; - Show all errors except for notices ; error_reporting = E_ALL & ~E_NOTICE and I ran the correct command cat | {remove comments command}, then I would end up with: error_reporting = E_ALL & ~E_NOTICE **Note** - I assumed that cat would be the best way to do this but I'm actually fine with the answer using another utility like awk, sed, egrep, etc.

Following this post as a reference, I'm able to run a

and

command without it throwing an error, but the filenames remain unchanged. Trying to strip **pronunciation_de_** from all mp3s in the current directory: pronunciation_de_wählen.mp3 pronunciation_de_wange.mp3 pronunciation_de_weil.mp3 pronunciation_de_werden.mp3 pronunciation_de_zentrum.mp3 Before troubleshooting the command, here's a quick sanity check:

. -name "*.mp3"

It returns all the mp3s in the current directory. Continuing on now that we know this part works...

--version

returns **sed (GNU sed) 4.4** I run

. -name "*.mp3" -exec sed -i 's/pronunciation_de_//g' {} \;

To make sure I'm fully understanding what's happening:

.

runs the **find** command in the current directory.

-name "*.mp3"

returns any .mp3 filetypes.

-exec

executes the next command you type.

-i

The **-i** switch means work on the actual files, not a (temporary) copy.
For

's/old_word/new_word/g'

: - The **s** sets sed to substitute mode. - **/old_word** is the word you want to replace. - **/new_word** is the word you want to replace with. In my example it'll be blank. - **/g** apply the replacement to all matches (not just the first).

{}

this string will be replaced by the filename during every iteration.

\;

the semicolon terminates the **find** command. The backslash escapes the semicolon character in case the shell tries to interpret it literally. Most of this information I'm getting from random blogs and Stack Exchange posts: Understanding the -exec option of find
What is meaning of {} + in find's -exec command? I really wanted to take my time and experiment and research before posting this almost-certainly-duplicate question but I'm completely stuck!

I want to automatically comment out a code block in PHP file, as below: The original block:

//	Enable all errors
	ini_set('display_startup_errors', 1);
	ini_set('display_errors', 1);
	error_reporting(E_ALL);

The new block with comments:

/* For the production version, the following codelines are commented
       out
	//	Enable all errors
	ini_set('display_startup_errors', 1);
	ini_set('display_errors', 1);
	error_reporting(E_ALL);
    */

So I plan to put these lines in two files and use sed to perform the replacement automatically. However, after searching online, I only find https://unix.stackexchange.com/questions/20322/replace-string-with-contents-of-a-file-using-sed?rq=1 and https://unix.stackexchange.com/questions/141387/sed-replace-string-with-file-contents , which means either only the source or destination pattern is in one file, and the remaining is in online. But no sample for both in files. So, how to perform the replacement? Should I use sed or awk?

Using zmv on macOS, I'd like to replace double-quotes (") in filenames with underscores (_). However, I'm having trouble getting the zshexpn to correctly isolate the ". Is there some magical zsh/zmv/zshexpn option I should be using?

% zmv -n '(**/)(*)' '$1${(S)2//"/_}'
zmv: syntax error in replacement
% zmv -n '(**/)(*)' '$1${(S)2//\"/_}'
zmv: syntax error in replacement`
% zmv -n '(**/)(*)' '$1${(Sp)2//\"/_}'
zmv: syntax error in replacement

(This is part of a much larger replace-illegal-characters engagement. I'm hoping to use one zmv expression to do the whole thing.) Thanks for any assistance.

So I have dump from U-boot and I need to replace specific string in CudaText editor. Here is mine text e101b1e0: 30ef27d8 e792f415 9beea618 5c601de4 .'.0..........`\ e101b1f0: aeaf9d25 e1dd63e9 536b005b 262a5ef4 %....c..[.kS.^*& hilinux # hilinux # md 0xe100f800 0x3E00 e100f800: 1422b556 4b603659 2ff6c4a4 5e24be15 V.".Y6`K.../..$^ e100f810: bdc025e2 c03d8966 d7120919 dc559b01 .%..f.=.......U. e100f820: 26f87c02 7d80db89 5c0d3e2a 37712c9d .|.&...}*>.\.,q7 e10173e0: 2be2a0fa 326d07a9 18cb4b7a 4db0a5ef ...+..m2zK.....M e10173f0: ddd7bcec 1fac59f7 17ca6be6 163ee297 .....Y...k....>. hilinux # hilinux # md 0xe100ba00 0x3E00 e100ba00: 33ffc17d 6cda1ed0 a38cfd95 68ffd26d }..3...l....m..h e100ba10: 98f71c20 54bf4927 bde58fa8 5782df84 ...'I.T.......W e100ba20: 789b7a0f feadd17f 07135d9e 48d2fef0 .z.x.....].....H I need delete text bellow hilinux # hilinux # md 0xe100f800 0x3E00 (new line is here) the hex number after md is increasing but it is in format 0x00000000. The expected text should look like this e101b1e0: 30ef27d8 e792f415 9beea618 5c601de4 .'.0..........`\ e101b1f0: aeaf9d25 e1dd63e9 536b005b 262a5ef4 %....c..[.kS.^*& e100f800: 1422b556 4b603659 2ff6c4a4 5e24be15 V.".Y6`K.../..$^ e100f810: bdc025e2 c03d8966 d7120919 dc559b01 .%..f.=.......U. e100f820: 26f87c02 7d80db89 5c0d3e2a 37712c9d .|.&...}*>.\.,q7 e10173e0: 2be2a0fa 326d07a9 18cb4b7a 4db0a5ef ...+..m2zK.....M e10173f0: ddd7bcec 1fac59f7 17ca6be6 163ee297 .....Y...k....>. e100ba00: 33ffc17d 6cda1ed0 a38cfd95 68ffd26d }..3...l....m..h e100ba10: 98f71c20 54bf4927 bde58fa8 5782df84 ...'I.T.......W e100ba20: 789b7a0f feadd17f 07135d9e 48d2fef0 .z.x.....].....H

PIN A
1 1:3 0:8
0 0:0

PIN B
1 1:0
0 0:0
Z Z:0

PIN C
1 1:3 0:8
0 0:0
Z Z:0

I would like to change the content on PIN A & PIN C only without affecting PIN B to

0 0:3
Z 0:3

Can't seem to find a way to replace without affecting the contents in PIN B using universal search and replace method:

perl -i -pe 's/0:0/0:3/g;' text
perl -i -pe 's/Z:0/Z:3/g;' text

Desired Output:

PIN A
1 1:3 0:8
0 0:3

PIN B
1 1:0
0 0:0
Z Z:0

PIN C
1 1:3 0:8
0 0:3
Z Z:3

When using sed to replace strings in-place, is there a way to make it report the changes it does (without relying on a diff of old and new files)? For instance, how can I change the command line find . -type f | xargs sed -i 's/abc/def/g' so I can see the changes that are made on the fly?

I'd like to know if it's possible to replace both filename.ext and a matched pattern inside its content regarding a pattern founded on the *filename* itself using sed (and grep also, maybe?). Let me show you as an example a few files that you may re-create with:

cat > ' Diary 2022 (essay, Travels).txt'  ' Diary 2022 (list, Recipes).txt'  ' Diary 2022 (watchlist, Movies-).txt'  ' Diary 2022 (list, Movies+).txt'  \(.+\s(\w.+)\)

I'd like things to became like this:

 Diary 2022 (essay, Travels).txt > becomes > travels.txt
and its content becomes >

TITLE/- travels -\TITLE @ sometext...

 Diary 2022 (watchlist, Movies-).txt > becomes > movies-.txt
and its content becomes >

TITLE/- movies- -\TITLE @ sometext...

 Diary 2022 (list, Movies+).txt > becomes > movies+.txt
and its content becomes >

TITLE/- movies+ -\TITLE @ sometext... ``` and so on...

The [dte editor](https://craigbarnes.gitlab.io/dte/#documentation) a small and easy to use console text editor. In readme or its online doc, both says: > * Regex [search](https://craigbarnes.gitlab.io/dte/dterc.html#search) and [replace](https://craigbarnes.gitlab.io/dte/dterc.html#replace) (are the key features). However, I haven't found how to do the replace anywhere yet. Even man dte doesn't mention anything about the replace operation, or how to get into the command mode to use it.

*This is homework!* I'm trying to replace all spaces in file names with an underscore in the yay directory. It asks me to use the commands xargs and sh without using $(command). I tried using conducts of commands, but it keeps displaying this message: sh: 1: Bad substitution Could someone explain why this message keeps popping up? Here's are the commands I tired using: find yay -type f -print0 | xargs -0 -I {} sh -c 'newname="${1// /_}"; mv "$1" "$newname"' sh AND find yay -type f -exec sh -c 'mv "$1" "${1// /_}"' _ {} \;

I have a load of CSS files in a folder and I want to be able to find and replace different values in all of these files in one go from the command line. So, for example, if I wanted to replace colour #dadce4 with #ececec can this easily be done with a single command? Just to be clear, I'm looking for something that will make the changes to all files within a directory and any sub directories without having to specify a file name.

I have some text in my paste buffer, e.g. I did a yw (yank word) and now I have 'foo' in my buffer. I now go to the word 'bar', and I want to replace it with my paste buffer. To replace the text manually I could do cw and then type the new word. How can I do a 'change word', but use the contents of my paste buffer instead of manually typing out the replacement word? The best option I have right now is to go to the beginning of the word I want to replace and do dw (delete word), go to the other place, and do the yw (yank word). Then go back to the replacement area and do p (paste) which is kind of clumsy, especially if they are not on the same screen.

Given a text, $ cat a.txt Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nam at magna sed libero accumsan ultrices. Proin varius tortor risus, at pulvinar quam auctor vitae. Etiam iaculis ipsum quis lacus convallis finibus. Nunc fermentum, nunc sit amet egestas congue, odio quam sollicitudin velit, quis venenatis augue nibh sed tortor. I can't remove that double empty lines using this command. $ tr '\n\n' '\n' < a.txt Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nam at magna sed libero accumsan ultrices. Proin varius tortor risus, at pulvinar quam auctor vitae. Etiam iaculis ipsum quis lacus convallis finibus. Nunc fermentum, nunc sit amet egestas congue, odio quam sollicitudin velit, quis venenatis augue nibh sed tortor. Replacing single new line with other char works, isn't it strange?