I did find a list of words in /usr/share/dict/words but I don't know if there's a way (an already existing way?) to split them up into their corresponding part of speech? Alternatively, I'm fine with any other suggestions, /usr/share/dict/words was only the first list of words I found.

sample input is output should be tid="8390500116294391399" ts="N/A" ets="2019-02-22T00:21:41.228Z" trxn="smaple data with spaces 2 record" trxn="smaple data with spaces 3rd record" trxn="smaple data with spaces 5th record" tid="2345500116294391399" ts="NA" ets="2017-02-22T00:21:41.228Z" trxn="other data with spaces" trxn="another record data" trxn="smaple data with spaces record" trxn="data with spaces" tid="2345500116294391399" ts="NA" ets="2017-02-22T00:21:41.228Z" I tried like below sed -e 's/trxn=/\ntrxn=/g' -e 's/tid=/\ntid=/g' -e 's/ts=/\nts=/g' while IFS= read -r var do if grep -Fxq "$trxn" temp2.txt then awk -F"=" '/tid/{print VAL=$i} /ts/{print VAL=$i} /ets/{print VAL=$i} /trxn/{print VAL=$i} /tid/{print VAL=$i;next}' temp2.txt >> out.txt else awk -F"=" '/tid/{print VAL=$i} /ts/{print VAL=$i} /ets/{print VAL=$i} /tid/{print VAL=$i;next}' temp2.txt >> out.txt fi done < "$input"

Basicaly I have dictionary from which I would like to remove words which contain two or more letters at any place in sentence for ex. bold leTTer reMoveMe quote lanGuaGe spaces Output should be like this bold quote space Is it possible to do it with seed ?

I'm trying to split text file into files of 1024 lines, so I ran split with the -d switch: split -d -l 300 ./list.lst I get some weird names: they start with x and the file names jump from x89 to x9000. I want the files to be named like that: 1.lst 2.lst 3.lst ... Thanks.

I need to print only words that consist of 3 characters, however the word document is a numbered list. Here's the exact question that I have to answer: > Using the sed command with [[:lower:]] character class on the animals file, find all the animal names that are only three characters long _(3 marks)_. This is what i have tried: cat animals | sed '/{[:lower:]].../d' cat animals | sed '/{[:lower:]]/d' sed '/[[:lower:]]{3}/d' animals This is the file I am trying to find the words from (the animals file): 01. aardvark 02. badger 03. cow 04. dog 05. elephant 06. fox 07. goose 08. horse 09. iguana 10. jackal 11. koala 12. lamb 13. mongoose 14. narwhal 15. onyx 16. pig 17. quail 18. rat 19. snake 20. tiger 21. umbrellabird 22. vulture 23. walrus 24. xerus 25. yak 26. zebra i have just found out the code cannot have the [[:lower:]] in it more than once is there a way to do this??

I have some dictionary to myspell in file.dic. Let's say: abc aword bword cab worda wordzzz and I'm looking for different words that are **permutations (or anagrams)** of each other. If there was a command "letter-sort" I'd do it more or less like that: cat file.dic | letter-sort | paste - file.dic | sort That gives me: abc abc abc cab adorw aword adorw worda bdorw bword dorwzzz wordzzz so now I clearly see anagrams in file. Is there such letters-sort command or how to obtain such result in maybe some other way?

I'm new to regex and found a command on a regex tutorial/test site that will allow me to search for 3 consecutive consonants. The only problem is I can't figure out how to use it with grep. Would someone help me out? I'm trying to search a word list text file using: (?:([bcdfghjklmnpqrstvwxzy])(?!.{1,2}\1)){3}

I seem to recall from comments on this site that the contents of arithmetic expansion **may** be word split, but I can't find the comment again. Consider the following code: printf '%d\n' "$(($(sed -n '/my regex/{=;q;}' myfile)-1))" If the sed command outputs a multi-digit number and $IFS contains digits, will the command substitution get word split before the arithmetic occurs? (I've already tested using extra double quotes: printf '%d\n' "$(("$(sed -n '/my regex/{=;q;}' myfile)"-1))" and this doesn't work.) ----- Incidentally the example code above is a reduced-to-simplest-form alteration of [this function](https://stackoverflow.com/a/35882480/5419599) that I just posted on Stack Overflow.